Question on: WAEC Physics - 1997
A ball of mass 0.1kg approaching a tennis player with a velocity of 10\(ms^{-1}\),is hit back in the opposite direction with a velocity of 15\(ms^{-1}\). If the time of impact between the racket and the ball is 0.01s, calculate the magnitude of the force with which the ball is hit
A
5000N
B
500N
C
250N
D
50N
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Correct Option: D
M =0.1kg; F=\(m\left(\frac{v-u}{t}\right) = 0.1\left(\frac{15-(-10)}{0.01}\right)\) F=50N
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