Question on: JAMB Mathematics - 2013
A basket contains 9 apples, 8 bananas and 7 oranges. A fruit is picked from the basket, find the probability that it is neither an apple nor an orange.
A
\(\frac{3}{8}\)
B
\(\frac{1}{3}\)
C
\(\frac{7}{24}\)
D
\(\frac{2}{3}\)
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Correct Option: B
n(apples) = 9
n(bananas) = 9
n(oranges) = 9
n((\varepsilon)) = 24
Hence Prob(not apple, nor orange) = Prob(banana) = (\frac{8}{24}) = (\frac{1}{3})
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