Question on: JAMB Mathematics - 2020
A binary operation x is defined by a x b = a\(^b\). If a x 2 = 2 - a, find the possible values of a?
A
1, -2
B
2, -1
C
2, -2
D
1, -1
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Correct Option: A
a = b = a\(^2\)
a + 2 = a\(^2\) - - - - - - - 1
a + 2 = 2 - a - - - - - - - - 2
Combining 1 & 2:
a\(^2\) = 2 - a
a\(^2\)+ a - 2 = a\(^2\) + a - 2 = 0
= (a + 2)(a - 1) = 0
a = 1 or - 2
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