A biologist has a 1 M solution of potassium hyd... - SS1 Chemistry Solutions and Concentration Question
A biologist has a 1 M solution of potassium hydroxide (KOH) and wants to prepare 250 mL of a 0.4 M KOH solution. How much water should be added to the stock solution?
62.5 mL
125 mL
150 mL
375 mL
150 mL
Using the dilution formula, we can calculate the volume of water (V2) to be added to the stock solution.
Given:
C1 (stock solution concentration) = 1 M
V1 (stock solution volume) = ?
C2 (diluted solution concentration) = 0.4 M
V2 (diluted solution volume) = 250 mL
Rearranging the dilution formula, we get:
V1 = (C2 × V2) / C1
Plugging in the values:
V1 = (0.4 M × 250 mL) / 1 M
V1 = 100 mL
To find the volume of water, subtract the stock solution volume from the desired diluted solution volume:
Volume of water = V2 - V1
Volume of water = 250 mL - 100 mL
Volume of water = 150 mL
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