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A biologist has a 1 M solution of potassium hyd... - SS1 Chemistry Solutions and Concentration Question

A biologist has a 1 M solution of potassium hydroxide (KOH) and wants to prepare 250 mL of a 0.4 M KOH solution. How much water should be added to the stock solution?

A

62.5 mL

 

B

125 mL

 

C

150 mL

 

D

375 mL

correct option: c

150 mL

Using the dilution formula, we can calculate the volume of water (V2) to be added to the stock solution.

 

Given:

C1 (stock solution concentration) = 1 M

V1 (stock solution volume) = ?

C2 (diluted solution concentration) = 0.4 M

V2 (diluted solution volume) = 250 mL

 

Rearranging the dilution formula, we get:

V1 = (C2 × V2) / C1

Plugging in the values:

V1 = (0.4 M × 250 mL) / 1 M

V1 = 100 mL

 

To find the volume of water, subtract the stock solution volume from the desired diluted solution volume:

Volume of water = V2 - V1

Volume of water = 250 mL - 100 mL

 

Volume of water = 150 mL

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