Question on: SS1 Chemistry - Solutions and Concentration
A biologist has a 1 M solution of potassium hydroxide (KOH) and wants to prepare 250 mL of a 0.4 M KOH solution. How much water should be added to the stock solution?
62.5 mL
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125 mL
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150 mL
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375 mL
150 mL
Using the dilution formula, we can calculate the volume of water (V2) to be added to the stock solution.
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Given:
C1 (stock solution concentration) = 1 M
V1 (stock solution volume) = ?
C2 (diluted solution concentration) = 0.4 M
V2 (diluted solution volume) = 250 mL
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Rearranging the dilution formula, we get:
V1 = (C2 × V2) / C1
Plugging in the values:
V1 = (0.4 M × 250 mL) / 1 M
V1 = 100 mL
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To find the volume of water, subtract the stock solution volume from the desired diluted solution volume:
Volume of water = V2 - V1
Volume of water = 250 mL - 100 mL
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Volume of water = 150 mL
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