A boat sails 8 km north from P to Q and then sa... - JAMB Mathematics 2023 Question
A boat sails 8 km north from P to Q and then sails 6 km west from Q to R. Calculate the bearing of R from P. Give your answer to the nearest degree.
217\(^o\)
323\(^o\)
037\(^o\)
053\(^o\)
To find the bearing of R from P, we need to determine the angle between the north direction and the line PR.
The distance PQ is 8 km north, and QR is 6 km west. We can use trigonometry to find the angle.
\[ \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} \]
\[ \tan(\theta) = \frac{6}{8} \]
\[ \theta = \tan^{-1}\left(\frac{6}{8}\right) \]
\[ \theta \approx 36.87^\circ \]
Now, the bearing is measured clockwise from the north direction. So, the bearing of R from P is:
\[ \text{Bearing} = 360^\circ - 36.87^\circ \]
\[ \text{Bearing} \approx 323.13^\circ \]
The nearest degree is **323°**.
Therefore, the correct answer is 323°
Add your answer
No responses