Question on: WAEC Physics - 2015
A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression
A
\(\frac{2u \text{sin}\theta}{g}\)
B
\(\frac{u^2 \text{sin}^2\theta}{2g}\)
C
\(\frac{u \text{sin}\theta}{g}\)
D
\(\frac{u \text{sin}\theta}{2g}\)
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Correct Option: C
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