Question on: WAEC Physics - 2012
A body is pulled through a distance of 500m by a force of 20N. If the power developed is 0.4kW, calculate the time for which the force acts
A
250.0s
B
25.0s
C
2.5s
D
0.5s
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Correct Option: B
t = \(\frac{FS}{P} = \frac{20 \times 500}{0.4 \times 1000}\)
= 25.0s
= 25.0s
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