Question on: WAEC Physics - 1991
A body moving with uniform acceleration has two points(5, 15) and (20, 60) on the velocity-times graph of its motion. Calculate
A
0.25ms-2
B
3.00ms-2
C
4.00ms-2
D
9.00ms-2
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Correct Option: B
slope = acceleration
a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)
= 3ms-2
a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)
= 3ms-2
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