# A body moving with uniform acceleration has two... - WAEC Physics 1991 Question

A body moving with uniform acceleration has two points(5, 15) and (20, 60) on the velocity-times graph of its motion. Calculate

A

0.25ms

^{-2}B

3.00ms

^{-2}C

4.00ms

^{-2}D

9.00ms

^{-2}**correct option:**b

slope = acceleration

a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)

= 3ms

a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)

= 3ms

^{-2}**Please share this, thanks:**

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