Question on: WAEC Physics - 2013
A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion
A
0.36J
B
0.72J
C
360.00J
D
720.00J
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Correct Option: A
P.E at max = K.E on projection
= (\frac{1}{2})mv2 = (\frac{1}{2} \times 0.02 \times 6^2 = 0.36J)
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