Question on: WAEC Physics - 2005
A body of mass 25kg, moving at 3ms-1 on a rough horizontal floor is at rest after sliding through a distance of 2.50m on the floor. Calculate the co-efficient of sliding friction. [g = 10.0ms-2]
A
0.09
B
0.18
C
0.36
D
0.54
Ask EduPadi AI for a detailed answer
Correct Option: B
a = \(\frac{v^2 - u^2}{2a} = \frac{0^2 - 3^2}{2 \times 2.5}\) = 1.8m/s2
F = ma = 25 x 1.8 = 45N
but \(\mu = \frac{F}{R} = \frac{45}{25 \times 10} = 0.18\)
F = ma = 25 x 1.8 = 45N
but \(\mu = \frac{F}{R} = \frac{45}{25 \times 10} = 0.18\)
Add your answer
Please share this, thanks!
No responses