Question on: JAMB Physics - 2004
A body of mass 4kg is acted on by a constant force of 12N for 3 seconds. The kinetic energy gained by the body at the end of the time is
A
144J
B
162J
C
81J
D
72J
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Correct Option: B
Here's how to solve the problem:
1. **Calculate acceleration (a):** Use Newton's second law, F = ma. Therefore, a = F/m = 12 N / 4 kg = 3 m/s².
2. **Calculate the final velocity (v):** Use the equation of motion v = u + at, where u (initial velocity) is 0 m/s (since the body starts from rest). So, v = 0 + (3 m/s² * 3 s) = 9 m/s.
3. **Calculate kinetic energy (KE):** Use the formula KE = (1/2)mv². Therefore, KE = (1/2) * 4 kg * (9 m/s
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