A body of mass m 0 5 kg is suspended by a strin... - WAEC Physics 1993 Question
A body of mass m = 0.5 kg is suspended by a string and pulled by a horizontal force of 1g N as shown in the 12N diagram: Calculate the tension T in the String if the body is in equilibrium. [Take g as 10ms-1]
A
7.0
B
10.9
C
12.5
D
13.0
correct option: d
Mg = 5N
T2 = 52 + 122T = 13N
T2 = 52 + 122T = 13N
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