Question on: JAMB Physics - 1991
A body of weight W N rest on a smooth plane inclined at an angle\(\theta\)o to the horizontal. What is the resolved part of the weight in Newtons along the plane?
A
W sin\(\theta\)
B
W cos\(\theta\)
C
W sec\(\theta\)
D
W tan\(\theta\)
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Correct Option: A
horizontal component = W cos(90o - \(\theta\))
= W sin
= W sin
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