Question on: JAMB Mathematics - 2018
A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.
A
\(\frac{2}{3}\)
B
\(\frac{1}{3}\)
C
\(\frac{1}{4}\)
D
\(\frac{1}{9}\)
Ask EduPadi AI for a detailed answer
Correct Option: D
Total number of balls = 2 + 4 = 6
P(of picking a red ball) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
P(of picking a blue ball) = \(\frac{4}{6}\) = \(\frac{2}{3}\)
With replacement,
P( picking two red balls) = \(\frac{1}{3}\) × \(\frac{1}{3}\) = \(\frac{1}{9}\)
Add your answer
Please share this, thanks!
No responses