Question on: JAMB Mathematics - 2018
A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.
A
\(\frac{2}{3}\)
B
\(\frac{1}{3}\)
C
\(\frac{1}{4}\)
D
\(\frac{1}{9}\)
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Correct Option: D
Total number of balls = 2 + 4 = 6
 P(of picking a red ball) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
 P(of picking a blue ball) = \(\frac{4}{6}\) = \(\frac{2}{3}\)
 With replacement,
 P( picking two red balls) = \(\frac{1}{3}\) × \(\frac{1}{3}\) = \(\frac{1}{9}\)
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