Question on: SS2 Physics - Electromagnetism
A capacitor has a capacitance of 5 μF and is charged to a voltage of 10 V. What is the charge stored on the capacitor?
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Given: C = 5 μF = 5 × 10(-6) F, V = 10 V
Q = C × V
Q = (5 × 10(-6) F) × (10 V)
Q = 50 × 10(-6) C
Q = 50 μC
Therefore, the charge stored on the capacitor is 50 μC.
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