Question on: JAMB Physics - 2001
A capacitor of 20 x 10-12F and an inductor are joined in series. The value of the inductance that will give the circuit a resonance frequency of 200kHz is
A
I/16 H
B
I/8 H
C
I/64 H
D
I/32 H
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Correct Option: D
Here's how to solve this problem:
1. **Recall the resonance frequency formula:** The resonance frequency (f) of an LC circuit is given by:
f = 1 / (2Ï€ * sqrt(L * C))
where:
* f is the resonant frequency in Hertz (Hz)
* L is the inductance in Henries (H)
* C is the capacitance in Farads (F)
2. **Convert the given frequency to Hz:**
The frequency is given as 200 kHz, which is equal to 200,000 Hz.
3. **Plug in the known values and solve for L:**
* f = 200,000 Hz
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