Question on: WAEC Physics - 1994
A cell of e.m.f. 1.5V and internal resistance of 2.5Ω is connected in series with an ammeter of resistance 0.5W and a resistor of resistance of 7.0Ω. Calculate the current in the circuit.
A
0.15A
B
0.20A
C
2.10A
D
3A
Ask EduPadi AI for a detailed answer
Correct Option: A
I =(\frac{E}{R+r} = \frac{1.5}{2.5+0.5+7}) = 0.15A
Add your answer
Please share this, thanks!
No responses