Question on: WAEC Physics - 1998
A cell of e.m.f. 1.5v is connected in series with a resistor of 3\(\Omega\). A high resistance voltmeter connected across the cell registers only 0.9v. Calculate the internal resistance of the cell
A
5.0\(\Omega\)
B
4.5\(\Omega\)
C
2.4\(\Omega\)
D
2.0\(\Omega\)
Ask EduPadi AI for a detailed answer
Correct Option: A
I = \(\frac{V}{R} = \frac{0.9}{3} = 3\)
r = \(\frac{E}{I} = \frac{1.5}{0.3} = 5\)
r = \(\frac{E}{I} = \frac{1.5}{0.3} = 5\)
Add your answer
Please share this, thanks!
No responses