Question on: WAEC Physics - 1998
A cell of e.m.f. 1.5v is connected in series with a resistor of 3(\Omega). A high resistance voltmeter connected across the cell registers only 0.9v. Calculate the internal resistance of the cell
A
5.0\(\Omega\)
B
4.5\(\Omega\)
C
2.4\(\Omega\)
D
2.0\(\Omega\)
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Correct Option: A
I = (\frac{V}{R} = \frac{0.9}{3} = 3)
r = (\frac{E}{I} = \frac{1.5}{0.3} = 5)
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