A certain radioisotope of 235 92 U emits four a... - JAMB Physics 1994 Question
A certain radioisotope of (^{235}_{92}U) emits four alpha particles and three beta particles. The mass number and the atomic number of the resulting elements respectively are
A
219 and 87
B
84 and 223
C
223 and 87
D
219 and 81
Ask EduPadi AI...
Correct Option: A
(^{235}{92}U) (\to) 4((^{4}{2}\alpha)) + 3((^{0}{-1}e)) + (^{b}{a}y)
a + (4 + 2) + (3x - 1) = 92 (\Rightarrow) a = 87
b + (4 x 4) + (3 x 0) = 235 (\Rightarrow) b = 219
(^{b}{a}Y) = (^{219}{87}Y)
Please share this, thanks:
#JAMB #JAMB
Add your answer
No responses