A charge of 4 6 10 -5 C is placed in an electri... - JAMB Physics 2023 Question
A charge of \(4.6 × 10^-5\)C is placed in an electric field of intensity \(3.2 × 10^4\) \(V^m-1\). What is the force acting on the electron?
1.5 N
3.7 N
4.2 N
2.5 N
The force (\(F\)) acting on a charged particle in an electric field is given by Coulomb's Law:
\[ F = q \cdot E \]
where:
- \( F \) is the force,
- \( q \) is the charge of the particle,
- \( E \) is the electric field intensity.
Given values:
\[ q = 4.6 \times 10^{-5} \, C \]
\[ E = 3.2 \times 10^{4} \, V/m \]
Now, plug in these values into the formula:
\[ F = (4.6 \times 10^{-5}) \cdot (3.2 \times 10^{4}) \]
\[ F \approx 1.472 \, N \]
The correct option is A: 1.5 N
The force acting on the charge in the electric field is approximately \(1.472 \, N\), and the closest option is \(1.5 \, N\).
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