Question on: JAMB Physics - 2023

The force (\(F\)) acting on a charged particle in an electric field is given by Coulomb's Law:

\[ F = q \cdot E \]

where:
- \( F \) is the force,
- \( q \) is the charge of the particle,
- \( E \) is the electric field intensity.

Given values:
\[ q = 4.6 \times 10^{-5} \, C \]
\[ E = 3.2 \times 10^{4} \, V/m \]

Now, plug in these values into the formula:

\[ F = (4.6 \times 10^{-5}) \cdot (3.2 \times 10^{4}) \]

\[ F \approx 1.472 \, N \]

The correct option is A: 1.5 N

The force acting on the charge in the electric field is approximately \(1.472 \, N\), and the closest option is \(1.5 \, N\).