Question on: WAEC Physics - 2005
a chemical cell of internal resistance 1(\Omega) supplies electric current to an external resistor of resistance 3(\Omega). Calculate the efficiency of the cell
A
75%
B
50%
C
33%
D
25%
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Correct Option: A
R = (r_1 + R = 1 + 3 = 4\Omega)
(\frac{3}{4} \times \frac{100}{1} = 75)%
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