Question on: WAEC Physics - 2005
a chemical cell of internal resistance 1\(\Omega\) supplies electric current to an external resistor of resistance 3\(\Omega\). Calculate the efficiency of the cell
A
75%
B
50%
C
33%
D
25%
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Correct Option: A
R = \(r_1 + R = 1 + 3 = 4\Omega\)
\(\frac{3}{4} \times \frac{100}{1} = 75\)%
\(\frac{3}{4} \times \frac{100}{1} = 75\)%
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