A chord subtends an angle of 120o at the centre... - WAEC Mathematics 2014 Question
A chord subtends an angle of 120o at the centre of a circle of radius 3.5cm. Find the perimeter of the minor sector containing the chord, [Take (\pi = \frac{22}{7})]
A
14\(\frac{1}{3}\)cm
B
12\(\frac{5}{6}\)cm
C
8\(\frac{1}{7}\)cm
D
7\(\frac{1}{3}\)cm
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Correct Option: A
perimeter of minor sector
2r + (\frac{\theta}{360} \times 2 \pi r)
= 2 x 3.5 + (\frac{120^o}{360^o} \times 2 \frac{22}{7} \times 3.5)
= 7 + (\frac{154}{21})
= 7 + 7.33
= 14.33
= 14(\frac{1}{3})cm
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