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A coil with 500 turns is exposed to a magnetic ... - SS1 Physics Electricity and Magnetism Question

A coil with 500 turns is exposed to a magnetic field of 0.02 T. If the magnetic field increases at a rate of 50 T/s, what is the magnitude of the induced emf in the coil?

 The magnitude of the induced emf can be calculated using Faraday's law:

   induced emf = -N x (ΔΦ/Δt)

   The change in magnetic flux can be calculated as ΔΦ = B x A, where B is the magnetic field and A is the area of the coil.

   Given: N = 500 turns, B = 0.02 T, Δt = 50 T/s

   Area of the coil, A = (π x r2) = (π x (0.1)2) = 0.0314 m2

   ΔΦ = B x A = 0.02 x 0.0314 = 0.000628 Wb

   induced emf = -N x (ΔΦ/Δt) = -500 x (0.000628/50) = -0.00628 V

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