A coin place below a rectangular glass block of... - JAMB Physics 2002 Question
A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of the coin is
A
3 cm
B
5 cm
C
6 cm
D
8 cm
correct option: a
Real depth = thickness of the glass block = 9cm.
Refractive index of the glass material = 1.5
But Refractive index = Real depth/Apparent depth
=> 1.5 = 9/Apparent depth
therefore Apparent depth = 9/1.5 = 6cm.
therefore Apparent displacement of the Coin = 9.6
= 3cm
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