Question on: WAEC Physics - 1997
A converging lens of focal length 15cm is used to obtain a real image magnified \(1\frac{1}{2}\) times. Calculate the distance of the image from the lens?
A
37.5cm
B
22.5cm
C
15cm
D
7.5cm
Ask EduPadi AI for a detailed answer
Correct Option: A
If u=x, v = \(1\frac{1}{2}x \Rightarrow if u= 2x,v=3x\
\frac{1}{f}=\frac{1}{u}+\frac{1}{v}; \frac{1}{15}=\frac{1}{2x}+\frac{1}{3x} \times \frac{5}{6}\
X=\frac{75}{76}=12.5, v=3x=12.5\times 3=37.5\)
\frac{1}{f}=\frac{1}{u}+\frac{1}{v}; \frac{1}{15}=\frac{1}{2x}+\frac{1}{3x} \times \frac{5}{6}\
X=\frac{75}{76}=12.5, v=3x=12.5\times 3=37.5\)
Add your answer
Please share this, thanks!
No responses