Question on: SS2 Physics - Geometrical Optics
A converging lens with a focal length of 10 cm is used to form an image of an object placed 20 cm in front of the lens. The image distance is:
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A
5 cm
B
10.5 cm
C
6.67 cm
D
40.56 cm
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Correct Option: C
Focal length (f) = 10 cm
Object distance (u) = -20 cm (negative sign indicates the object is placed in front of the lens)
1/10 = 1/v - 1/-20
1/10 = (20 - v) / (20v)
20v = 10(20 - v)
20v = 200 - 10v
30v = 200
v = 200 / 30
v ≈ 6.67 cm
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