Question on: JAMB Physics - 2002
A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowing in 1h is
A
2g
B
6g
C
10g
D
18g
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Correct Option: A
From Faradays Law, mass deposited during electrolysis is given by
M = ItZ
=> Z = M/(It)
For a current of 1.5A flowing for 1h, the mass M, deposited is given by
M= ZiT
= 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1
= 2.0g
M = 2.0g
M = ItZ
=> Z = M/(It)
| = | __2 |
| 0.5x3x60x60 |
For a current of 1.5A flowing for 1h, the mass M, deposited is given by
M= ZiT
= 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1
= 2.0g
M = 2.0g
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