Question on: SS1 Physics - Scalar And Vector Quantities
A displacement vector D has a magnitude of 12 m and is directed at an angle of 45 degrees with the positive x-axis. Resolve the displacement vector into its x and y components
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Given:
Magnitude of displacement (D) = 12 m
Angle with the x-axis (θ) = 45 degrees
To find the x and y components, we can use the same trigonometric relationships:
Dx = D X cos(θ)
Dy = D X sin(θ)
Calculating the components:
Dx = 12 m X cos(45 degrees) = 12 m X 0.707 = 8.49 m
Dy = 12 m X sin(45 degrees) = 12 m X 0.707 = 8.49 m
The x component of the displacement vector is 8.49m, and the y component is 8.49m.
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