A diverging lens has a focal length of -15 cm A... - SS2 Physics Geometrical Optics Question

Focal length (f) = -15 cm (negative sign indicates a diverging lens)

Object distance (u) = 30 cm

Using the lens formula, 1/f = 1/v - 1/u, we can find the image distance (v).

1/(-15) = 1/v - 1/30

To simplify the equation, we can take the common denominator:

-2/30 = (30 - v) / (30v)

Now, we can cross-multiply and solve for v:

-2v = (30 - v) x 30

-2v = 900 - 30v

28v = 900

v = 900 / 28

v ≈ 32.14 cm

The image distance (v) is approximately 32.14 cm.

To calculate the magnification (M), we can use the formula M = -v / u, where M represents the magnification.

M = -(32.14) / 30

M ≈ -1.07

The magnification is approximately -1.07.

Therefore, the image distance is approximately 32.14 cm and the magnification is approximately -1.07.