Question on: WAEC Mathematics - 2006
A fair coin is tossed three times. Find the probability of getting two heads and one tail.
A
\(\frac{1}{2}\)
B
\(\frac{3}{8}\)
C
\(\frac{1}{4}\)
D
\(\frac{1}{8}\)
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Correct Option: B
Pr(head) = \(\frac{1}{2}\), Pr(tail) = \(\frac{1}{2}\):Pr(2 heads)
= \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\)
Pr(2 heads and tail) 3 times
= (\(\frac{1}{4}\) x \(\frac{1}{2}\)) x 3
= \(\frac{3}{8}\)
= \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\)
Pr(2 heads and tail) 3 times
= (\(\frac{1}{4}\) x \(\frac{1}{2}\)) x 3
= \(\frac{3}{8}\)
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