Question on: JAMB Physics - 1994
A force of 15N stretches a spring to a total length of 30cm. An additional force of 10N stretches the spring 5cm further. Find the natural length of the spring
A
25.0cm
B
22.5cm
C
20.0cm
D
15.0cm
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Correct Option: B
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm
L = 22.5cm
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