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A galvanometer has a resistance of 5 By using a... - JAMB Physics 1999 Question

A galvanometer has a resistance of 5Ω. By using a shunt wire of resistance 0.05Ω, the galvanometer could be converted to an ammeter capable of reading 2Amp. What is the current through the galvanometer?
A
2mA
B
10mA
C
20mA
D
25mA
correct option: c

Shunt resistance is usually given as

R = igrg/(I - ig)

Where R = 0.05Ω

rg = 5Ω

I = 2M

∴ ig = IR/(rg + R)

= (2 x 0.05)/(5 + 0.05)

= 0.10/5.05

= 0.0198A

= 19.8mA

= 20mA

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