A galvanometer of internal resistance 50 Omega ... - WAEC Physics 2010 Question
A galvanometer of internal resistance 50\(\Omega\) and full scale deflection of 20 mA is converted into a voltmeter by connecting a resistor of resistance 1950\(\Omega\) in series to it. Calculate the maximum voltage that can be read by the voltmeter
A
20V
B
30V
C
38V
D
40V
correct option: d
V = IR1 + IR2
= 0.02 x 50 + 0.02 x 1950 = 40V
= 0.02 x 50 + 0.02 x 1950 = 40V
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