Question on: JAMB Chemistry - 2014

A hydrocarbon has an empirical formula CH and a vapour density of 39. Determine its molecular formula.

[C = 12, H = 1]

A
C2H6
B
C3H8
C
C3H4
D
C6H6
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Correct Option: D

molecular mass = 2 x vapour density

= 2 x 39 = 79

∴ Cn Hn = 78

12n + 1n = 78

13n = 78

n = (\frac{78}{13}) = 6

∴ Cn Hn = C 6H 6

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