Question on: WAEC Physics - 2003
A lamp is rated 240V 60W, calculate the resistance of its filament
A
240\(\Omega\)
B
360\(\Omega\)
C
960\(\Omega\)
D
1440\(\Omega\)
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Correct Option: C
R = (\frac{V^2}{P} = \frac{240^2}{60} = 960\Omega)
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