A lorry accelerates uniformly in a straight lin... - JAMB Physics 2023 Question
A lorry accelerates uniformly in a straight line with acceleration of \(4ms^-2\) and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?
650
900
800
250
The lorry's initial velocity (u) is found using the formula \(s = ut + \frac{1}{2}at^2\). Given that \(a = 4 \, \text{m/s}^2\), \(s = 250 \, \text{m}\), and \(t = 10 \, \text{s}\):
\[
250 = 10u + \frac{1}{2} \times 4 \times (10^2) \\
250 = 10u + 200 \\
10u = 50 \\
u = 5 \, \text{m/s}
\]
For the next 10 seconds (\(t = 20 \, \text{s}\)), we use the formula \(s = ut + \frac{1}{2}at^2\) again:
\[
s = (5 \times 20) + \frac{1}{2} \times 4 \times (20^2) \\
s = 100 + 800 \\
s = 900 \, \text{m}
\]
The distance covered in the next 10 seconds is \(900 \, \text{m}\). Subtracting the initial distance (250 m), we get \(900 - 250 = 650 \, \text{m}\).
Therefore, the correct answer is: \(650 \, \text{m}\).
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