Question on: WAEC Physics - 2004
A machine of velocity ratio 5 is used in lifting a load with an effort of 500N. If the machine is 80% efficient. Determine the magnitude of load
A
2500N
B
2000N
C
900N
D
625N
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Correct Option: B
M.A = \(\frac{Eff \times V.r}{100} = \frac{80 \times 5}{100} = 4\)
Load = effort x M.A
= 4 x 500 = 2000N
Load = effort x M.A
= 4 x 500 = 2000N
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