Question on: SS2 Physics - Electromagnetism

A magnetic field of 0.5 T is directed perpendicular to a circular loop with a radius of 0.1 m. If the magnetic field decreases to zero in 0.2 seconds, what is the magnitude of the induced emf in the loop?

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The magnitude of the induced emf can be calculated using Faraday's Law:

   emf = -N x d(BA)/dt,

  where N is the number of turns in the loop, B is the magnetic field, A is the area of the loop, and dt is the change in time.

   Given:

   N = 1 (single loop)

   B = 0.5 T

   A = π x (0.1 m)2 = 0.0314 m2

  dt = 0.2 s

   Plugging these values into the formula:

   emf = -1 x (0.5 T) x (0.0314 m2) / (0.2 s)

  emf = -0.025 V

  The magnitude of the induced emf is 0.025 V (rounded to two decimal places).

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