Question on: WAEC Mathematics - 2014
A man's eye level is 1.7m above the horizontal ground and 13m from a vertical pole. If the pole is 8.3m high, calculate, correct to the nearest degree, the angle of elevation of the top of the pole from his eyes.
A
33o
B
32o
C
27o
D
26o
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Correct Option: C
tan \(\theta = \frac{opp}{adj} = \frac{6.6}{13}\)
tan \(\theta = 0.5077\)
\(\theta\) = tan-1 0.5077
\(\theta = 27^o\)
tan \(\theta = 0.5077\)
\(\theta\) = tan-1 0.5077
\(\theta = 27^o\)
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