Question on: WAEC Physics - 2011
A metal rod of density 7000 kgm-3 and cross-sectional area of 0.001257m2 has a mass of 1.76kg. Calculate its length.
A
0.20m
B
0.25m
C
0.40m
D
0.50m
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Correct Option: A
P = \(\frac{M}{AL}\)
L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m
L = \(\frac{M}{CA}\)
= \(\frac{1.76}{7000 \times 0.001257}\)
= 0.2m
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