Question on: WAEC Physics - 1994
A metal rod of length 40cm at 20°C is heated to a temperature of 45°C. If the new length of the rod is 40.05cm. Calculate its linear expansitivity
A
1.2 x \(10^{-5}K{-1}\)
B
2.5x \(10^{-5}K{-1}\)
C
3.5x \(10^{-5}K{-1}\)
D
4.5x \(10^{-5}K{-1}\)
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Correct Option: E
(\alpha = \frac{I_2-I_1}{I_1(\theta_2-\theta_1)} \ \Rightarrow \frac{40.05 - 40}{40 \times (45-20)} = 5.0 \times10^{-5})
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