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A metal surface is irradiated with light of wav... - SS2 Physics Modern Physics - Quantum Mechanics Question

A metal surface is irradiated with light of wavelength 500 nm. If the work function of the metal is 2.0 eV, calculate the maximum kinetic energy of the emitted electrons.

To calculate the maximum kinetic energy of the emitted electrons, we need to convert the given wavelength to frequency using the formula: f = c / λ, where f is the frequency, c is the speed of light (3.0 × 108 m/s), and λ is the wavelength.

f = (3.0 × 108 m/s) / (500 × 10-9 m) = 6.0 × 1014 Hz

Now, we can calculate the energy of the incident photons using the formula: E = hf.

E = (6.63 × 10-34 J·s) × (6.0 × 1014 Hz) = 3.98 × 10-19 J

The maximum kinetic energy of the emitted electrons can be calculated by subtracting the work function from the energy of the incident photons:

Kinetic energy = E - Work function

Kinetic energy = (3.98 × 10-19 J) - (2.0 eV × 1.6 × 10-19 J/eV) 

= 1.38 × 10-19 J

 

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