A missile is launched with a speed of 75 ms-1 a... - JAMB Physics 2023 Question
A missile is launched with a speed of 75 ms-1 at an angle of 22° above the surface of a warship. Find the horizontal range achieved by the missile. Ignore the effects of air resistance.
[Take g = 10 ms-1]
A
195
B
271 m
C
391 m
D
136 m
correct option: c
The horizontal range (R) of a projectile launched at an angle can be calculated using the formula:
\[ R = \frac{v^2 \sin(2\theta)}{g} \]
where:
- \( v \) is the initial speed of the projectile,
- \( \theta \) is the launch angle,
- \( g \) is the acceleration due to gravity.
In this case, \( v = 75 \, \text{m/s} \), \( \theta = 22^\circ \), and \( g = 10 \, \text{m/s}^2 \).
\[ R = \frac{(75)^2 \sin(2 \times 22^\circ)}{10} \]
Calculating this expression yields approximately 391 m.
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