Question on: JAMB Chemistry - 1997
A mixture of 0.20 mole of Ar, 0.20 mole of N2 and 0.30 mole of He exerts a total pressure of 2.1 atm. The partial pressure of He in the mixture is?
A
0.90 atm
B
0.80 atm
C
0.70 atm
D
0.60 atm
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Correct Option: A
Total no mole = 0.2 + 0.2 + 0.3 = 0.7
Partial pressure of He = (0.3)/(0.7) x 2.1 =0.90
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