A nuclide is represented by \(_{32}^{70}B\). Determine its neutron-proton ratio
index-0
0.5
index-1
0.8
index-2
1.2
index-3
1.5
Correct Answer:
C
The element B has a mass number 70 and atomic number 32.
Hence, B has 32 protons and (70-32) = 38 neutrons.
The neutron to proton ratio is 38:32 = \(\frac{38}{32} = 1.1875\)
\(\approxeq 1.2\)