Question on: WAEC Physics - 2003
A piece of metal of relative density 5.0 weighs 60N in air. Calculate its weight when fully immersed in water
A
4N
B
5N
C
48N
D
60N
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Correct Option: C
R.D = (\frac{m}{m - m_2} = 5 = \frac{6}{60 - m_1} = \frac{240}{5} = 48N)
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