Question on: JAMB Physics - 1992
A platinum resistance thermometer wire has a resistance of 5 ohms at 0oC and 5.5 ohms at 100oC. Calculate the temperature of the wire when the resistance is 5.2 ohms
A
80oC
B
60oC
C
40oC
D
10oC
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Correct Option: C
100oC .... 5.5
\(\theta\)oC .... 5.3
0oC .... 5.0
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{5.5 - 5 .0}{5.5 - 5.0}\)
\(\theta\) = 40oC
\(\theta\)oC .... 5.3
0oC .... 5.0
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{5.5 - 5 .0}{5.5 - 5.0}\)
\(\theta\) = 40oC
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