Question on: WAEC Physics - 2013
A potential difference of 12V is applied across the ends of a 6(\Omega) resistor for 10 minutes. Determine the quantity of heat generated
A
720J
B
1200J
C
14400J
D
43200J
Ask EduPadi AI for a detailed answer
Correct Option: C
Q = (\frac{V^2 t}{R} = \frac{12^2 \times 10 \times 60}{6})
= 14400J
Add your answer
Please share this, thanks!
No responses