Question on: SS2 Physics - Mechanics - Motion in a Plane
A projectile is launched at an angle of 45 degrees above the horizontal with an initial velocity of 20 m/s. Neglecting air resistance, what is the horizontal component of its velocity?
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A
20 m/s
B
10 m/s
C
14.1 m/s
D
0 m/s
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Correct Option: B
Explanation: The horizontal component of velocity remains constant throughout the motion of a projectile. In this case, the initial velocity is given as 20 m/s, and the launch angle is 45 degrees. The horizontal component of velocity can be found using the formula:
Horizontal component of velocity = Initial velocity x cos(angle)
Horizontal component of velocity = 20 m/s x cos(45°) = 20 m/s x 0.707 ≈ 10 m/s
Therefore, the horizontal component of the velocity of the projectile is 10 m/s.
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