Question on: JAMB Physics - 2024

A rectangular solid black has length 10 cm, breadth 5 cm, and height 2 cm. If it lies on a horizontal surface, and has density 100 kg/m3, calculate the pressure it exerts on the surface.

A
200 N/m2
B
300 N/m2
C
100 N/m2
D
400 N/m2
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Correct Option: A

To calculate the pressure exerted by the rectangular solid, we use the formula: Pressure = Force / Area. The force is the weight of the solid, and the area is the area of contact with the surface.

First, calculate the volume of the rectangular solid:

Volume = length * breadth * height = 10 cm * 5 cm * 2 cm = 100 cm3

Convert the volume to m3: 100 cm3 = 100 * (1/100)3 m3 = 100 * 10-6 m3 = 1.0 * 10-4 m3

Calculate the mass of the solid using the density:

Density = Mass / Volume => Mass = Density * Volume = 100 kg/m3 * 1.0 * 10-4 m3 = 0.01 kg

Calculate the weight of the solid (Force) using the acceleration due to gravity (g = 9.8 m/s2). We will approximate g as 10 m/s2 for simplicity.

Weight = Mass * g = 0.01 kg * 10 m/s2 = 0.1 N

The area of contact with the surface is the length times the breadth: Area = 10 cm * 5 cm = 50 cm2

Convert the area to m2: 50 cm2 = 50 * (1/100)2 m2 = 50 * 10-4 m2 = 5.0 * 10-3 m2

Calculate the pressure:

Pressure = Force / Area = 0.1 N / (5.0 * 10-3 m2) = 20 N/m2

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